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Consider the reaction of 2-chloro-2-methylpentane with sodium iodide. Assuming no other changes, how would it affect...

Consider the reaction of 2-chloro-2-methylpentane with sodium iodide.

Assuming no other changes, how would it affect the rate if one simultaneously doubled the concentration of 2-chloro-2-methylpentane and sodium iodide?

A) No effect.

B) It would double the rate.

C) It would triple the rate.

D) It would quadruple the rate.

E) It would increase the rate five times.

Science   Chemistry   
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Answer #1

Answer – We are given the reaction of 2-chloro-2-methylpentane with sodium iodide and we know this is the SN1 reaction, since the 2-chloro-2-methylpentane is the tertiary alkyl halide and it is form more stable carbocation. This step is the rate determine step. So reaction rate is depending on the 2-chloro-2-methylpentane. So as we double the concentration of 2-chloro-2-methylpentane the rate also get double.

So answer for this one is B) It would double the rate.

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