Perform the following calculations to the correct number of significant figures.
1- [(1.9×106)÷(2.54×105)]+7.86
2-(570.15−237.0)÷5.1
3- (9013+43−9.4)×(8.6×106)
4-(3.00×2.4694)−2.09
1- [(1.9×106)÷(2.54×105)]+7.86 = [ 201.4 ÷ 266.7]+7.86
= 0.755 +7.86 = 8.615 four significant figures
2-(570.15−237.0)÷5.1 = 333.15÷ 5.1 = 65.32 four significant figures
3- (9013+43−9.4)×(8.6×106) =
9046.6×911.6 = 8246880.56 = 8.246×10^6
= four significant figures
4-(3.00×2.4694)−2.09 = 7.4082-2.09 = 5.3182 five significant figures
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