Question

An atom emits a photon (bundle) of light having wavelength 486 nm. What is the frequency of the light? What is the energy of the photon?

Answer 1

wavelength = 486 nm = 486 x 10^-9 m

frequency v = C /

                    = 3 x 10^8 / 486 x 10^-9

                     = 6.17 x 10^14 Hz

frequency v = 6.17 x 10^14 Hz

Energy = h v

             = 6.625 x 10^-34 x 6.17 x 10^14

             = 4.09 x 10^-19 J

Energy = 4.09 x 10^-19 J