What is the sum of the oxidation numbers of all the atoms in each of the following polyatoic ions?
A.) OH-
B.) NH4+
C.) SO42-
D.) PO43-
A.) OH-
Oxidation number of O = -2
Oxidation number of H =+1
the sum of the oxidation numbers of all the atoms = -2+1=-1
B.) NH4+
Oxidation number of O = -2
Oxidation number of H =+1
Oxidation number of N =-3
the sum of the oxidation numbers of all the atoms = 4*+1+(-3) = +1
C.) SO42-
Oxidation number of O = -2
Oxidation number of S =+6
the sum of the oxidation numbers of all the atoms = 4(-2)+6 = -8+6=-2
D.) PO43-
Oxidation number of O = -2
Oxidation number of P =+5
the sum of the oxidation numbers of all the atoms = 4(-2)+5 = -8+5=-3
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