Ans :
A)
The heat of combustion = 26.38 KJ/g = 26380 J/g
The amount of heat released = mass x heat of combustion
= 1.670 x 26380
= 44054.6 J
Now the heat absorbed = specific heat of calorimeter x change in temperature
44054.6 = c x (27.60 - 22.45)
c = 8554.3 J/oC
= 8.554 KJ/oC
B)
Here change in temperature = 26.82 - 22.14 = 4.68oC
heat absorbed by calorimeter = specific heat x change in temperature
= 8.554 x 4.68
= 40.03 KJ
So heta released by the substance is 40.03 KJ
heat of combustion per gram = 40.03 / 1.390
= 28.8 KJ/g
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