Question

1. Define standard heat of fusion (∆H°fus ) and standard heat of vaporization (∆H°vap ). Explain...

1. Define standard heat of fusion (∆H°fus ) and standard heat of vaporization (∆H°vap ). Explain why the standard heat of fusion (∆H°fus ) is less than the standard heat of vaporization (∆H°vap ) for most substances

Homework Answers

Answer #1

standard heat of fusion (∆H°fus ) = The amount of heat absorbed when one mole of a solid substance converts into liquid at its melting point.

  standard heat of vaporization (∆H°vap )   = The amount of heat absorbed when one mole of a liquid substance converts into vapor at its boiling point.

for most of the substances, ∆H°vap   >    ∆H°fus  

because generally Boilingpoint of the substance greatertha its meltingpoint.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
experiment to determine the latent heat of fusion of ice and the latent heat of vaporization...
experiment to determine the latent heat of fusion of ice and the latent heat of vaporization of steam
Using heat of fusion, specific heat of water, and/or heat of vaporization, calculate the amount of...
Using heat of fusion, specific heat of water, and/or heat of vaporization, calculate the amount of heat energy in each of the following. (a) calories to condense 141 g of steam at 100
If the heat of fusion for water is 6.01 kJ/mol, the heat of vaporization is 40.79...
If the heat of fusion for water is 6.01 kJ/mol, the heat of vaporization is 40.79 kJ/mol, calculate the heat transferred during the deposition of 2.0 g water vapor. Deposition is the phase change from a vapor to a solid.
The heat of fusion of water is 79.9 cal/g, the heat of vaporization of water is...
The heat of fusion of water is 79.9 cal/g, the heat of vaporization of water is 540 cal/g, and the specific heat of water is 1.00 cal/deg/g. How many grams of ice at 0 ° could be converted to steam at 100 °C by 9,076 cal of heat?
Using the values for the heat of fusion, specific heat of water, and/or heat of vaporization,...
Using the values for the heat of fusion, specific heat of water, and/or heat of vaporization, calculate the amount of heat energy in each of the following: A. joules needed to melt 90.0 g of ice at 0 ∘C and to warm the liquid to 85.0 B. kilocalories released when 30.0 g of steam condenses at 100 ∘C and the liquid cools to 0 ∘C C. kilojoules needed to melt 26.0 g of ice at 0 ∘C, warm the liquid...
The latent heat of vaporization (Lv) is similar to the latent heat of fusion (Lf), except...
The latent heat of vaporization (Lv) is similar to the latent heat of fusion (Lf), except that it relates to boiling rather than melting. For water, Lv = 2.26 x 106 J/kg. .970 kg of steam at 100°C (the boiling point of water) is put in contact with a 13.5 kg piece of metal. The initial temperature of the piece of metal is 70.0°C. When the piece of metal reaches 100°C, .0420 kg of steam has condensed.     a.         How much heat...
The latent heat of vaporization (Lv) is similar to the latent heat of fusion (Lf), except...
The latent heat of vaporization (Lv) is similar to the latent heat of fusion (Lf), except that it relates to boiling rather than melting. For water, Lv = 2.26 x 106 J/kg. .970 kg of steam at 100°C (the boiling point of water) is put in contact with a 13.5 kg piece of metal. The initial temperature of the piece of metal is 70.0°C. When the piece of metal reaches 100°C, .0420 kg of steam has condensed.     a.         How much heat...
The latent heat of vaporization (Lv) is similar to the latent heat of fusion (Lf), except...
The latent heat of vaporization (Lv) is similar to the latent heat of fusion (Lf), except that it relates to boiling rather than melting. For water Lv = 2.26 x 10^6 J/kg. .970 kg of steam at 100 degrees celsius (the boiling point of water) is put in contact with a 13.5 kg piece of metal. The initial temperature of metal piece is 70.0 degree celsius. When the piece of metal reaches 100 degrees celsius, .0420 kg of steam has...
Calculate ΔvapH , the molar enthalpy of vaporization, of a substance at 338.15 K, given that...
Calculate ΔvapH , the molar enthalpy of vaporization, of a substance at 338.15 K, given that its standard enthalpy of vaporization is Δvap Hθ = 32.45 kJ mol−1 vap at 25.0ºC. The heat capacities are Cp,mliq = 46.20 J K−1 mol−1 for the liquid and Cp,mvap = 32.20 J K−1 mol−1 for the vapor.
Why is the heat of vaporization of a molecule with a molecular mass of 346.2 g/mol...
Why is the heat of vaporization of a molecule with a molecular mass of 346.2 g/mol higher than the heat of vaporization of a molecule with a molar mass of 157.4 g/mol?
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT