Question

61.0 mL of a 1.80 M solution is diluted to a total volume of 238 ML. A 119 mL portion of that solution is diluted by adding 111 mL of water. What is the final concentration? Assume the volumes are additive.

Answer 1

Solution :-

Using the dilution formula we can calculate the concnetrations of the diluted solution.

lets first calculate the molarity of the 238 ml solution

M1V1 = M2V2

M2 = M1*V1/V2

     = 1.80 M * 61.0 ml / 238 ml

     = 0.46134 M

now using this concnetration of the 238 ml solution we can find the concentration of the diluted solution made by adding 111 ml water to 119 ml solution in above part

total volume = 119 ml + 111 ml = 230 ml

M1= 0.46134 M

V1 = 119 ml

M2 = ?

V2 = 230 ml

M2 = M1V1/V2

     = 0.46134 M * 119 ml / 230 ml

     = 0.2387 M

So the molarity of the final diluted solution is 0.2387 M