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mass perc to mola flow In the production of a drug having a molecular weight of...

mass perc to mola flow

In the production of a drug having a molecular weight of 28.7, the aqueous exit stream from the reactor flows at the rate of 10.9 L/min. The drug concentration is 42%, and the specific gravity of the solution is 1.079. Calculate the flow rate of the drug in kmol/min.

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Answer #1

PM=28,7

Q=10,9L/min

ge=1,079

ge= ρmixture/ρreference

Since it is a liquid mixture, the reference water density 1kg / L is taken

ρmixture=ge.ρmixture=1kg/L.1,079= 1,079kg/L

ρ=mass/Volume

Taking into account a calculation based on 1 minute

massmixture=ρmixture.Volumemixture=1,079kg/L.10,9L= 11,7611kg

Concentration=massdrugx100/massmixture

massdrug=concentrationxmassmixture/100= (42x11,7611kg)/100= 4,9397kg

molesdrug=massdrug/PMdrug= 4,9397kg/(28,7kg/kmol)=0,1721kmol

it returning calculation based is obtained the flow rate of the drug in kmol/min = 0,1721kmol/min

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