calculate the work for an ideal gas that is compressed from 2L to 1L by a constant external pressure at 2 bar at 25 degrees celsius
Pressure = p = 2 bar ( 1 bar = 0.9869 atm)
p = 1.9738 atm
V = 2-1 = 1L
work = W= PV = 1.9738 x 1= 1.9738 L-atm
but 1L-atm = 101.3 j
1.9738 L-atm = 101.3 x 1.9738 = 199.946 J
workdone on the system = W = 199.946J = 0.199 KJ
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