Background info: Vinegar contains acetic acid, CH3COOH. You can determine the mass of acetic acid in a vinegar sample by titrating with sodium hydroxide of known concentration. The reaction: CH3OOH(AQ) +NaOH(aq)=> CH3COONa(aq)+H2O(l). I have determined the grams of acetic acid to be 60. There are 25 ml sample of vinegar requiring 41.33 mL of a .953 M solution of NaOH by titrating sodium hydroxide of known concentration.
** THE QUESTION IS: What is the molar concentration of the acetic acid in the vinegar? **
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