Question

Consider the redox reaction 2VO4^3-(aq) + SO2(g) + 8H^+(aq)--->2VO^2+(aq)+SO4^2-(aq)+4H2O(L) the oxidizing agent is VO4^3-(aq), VO2^+(aq), H^+(aq),...

Consider the redox reaction

2VO4^3-(aq) + SO2(g) + 8H^+(aq)--->2VO^2+(aq)+SO4^2-(aq)+4H2O(L)

the oxidizing agent is VO4^3-(aq), VO2^+(aq), H^+(aq), SO2(g), SO4^2-(aq)

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Answer #1

2VO4^3-(aq) + SO2(g) + 8H^+(aq)--->2VO^2+(aq)+SO4^2-(aq)+4H2O(L)

oxidizing agent = the one that is being reduced

agents are found in the "reactants" part so

2VO4^3-(aq) + SO2(g) + 8H^+(aq) must be the answer

SO2 --> S(+4)

SO4-2 --> S(+6)

S is losing 2 electrons, thereore it is being oxidized, this is the reducing agent

therefore

2VO4^-3 must be the oxidizing agent

makes sense, since it is losing oxigens, therefore it is giving Oxygen to oxidize other substances

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