Question

In the reaction of phosphorus with chlorine to form a phosphorus chloride, whether PCl3 or PCl5...

In the reaction of phosphorus with chlorine to form a phosphorus chloride, whether PCl3 or PCl5 forms depends on

1) whether the reaction is carried out in the gas phase or in solution.

2) the amount of chlorine present.

3) whether the chlorine used is molecular or atomic.

4) the amount of moisture present.

5) which allotropic form of phosphorus is used

Homework Answers

Answer #1

Answer: 1) whether the reaction is carried out in the gas phase or in solution.

Phosphorus trichloride, PCl3, is prepared by the action of chlorine on white or red phosphorus on heating in a retort, and condensing the phosphorus trichloride vapour in a cooled dry receiver.

2P + 3Cl2 = 2 PCl3

Phosphorus pentachloride, PCl5 is prepared by passing chlorine into a well cooled solution of phosphorus in carbondisulphide and crystallizing out the product formed.

2P + 5Cl2 = 2 PCl5

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Phosphorus pentachloride gas decomposes to form phosphorus trichloride gas and chlorine gas. What is the equilibrium...
Phosphorus pentachloride gas decomposes to form phosphorus trichloride gas and chlorine gas. What is the equilibrium constant for this reaction if a reaction vessel has an initial concentration of phosphorus pentachloride of 0.500 M and the equilibrium concentration of 0.119 M? Neither chlorine gas nor phosphorus trichloride are present in the initial reaction vessel. Assume a 1.00 L reaction vessel. Thank you
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) You are...
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) You are given 10.0 g of aluminum and 15.0 g of chlorine gas. If you had excess chlorine, how many moles of of aluminum chloride could be produced from 10.0 g of aluminum?
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) You are...
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) You are given 26.0 g of aluminum and 31.0 g of chlorine gas. A) If you had excess chlorine, how many moles of of aluminum chloride could be produced from 26.0 g of aluminum? B)If you had excess aluminum, how many moles of aluminum chloride could be produced from 31.0 g of chlorine gas, Cl2?
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) What is...
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) What is the maximum mass of aluminum chloride that can be formed when reacting 23.0 g of aluminum with 28.0 g of chlorine?
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) What is...
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction: 2Al(s)+3Cl2(g)→2AlCl3(s) What is the maximum mass of aluminum chloride that can be formed when reacting 12.0 g of aluminum with 17.0 g of chlorine? Express your answer to three significant figures and include the appropriate units. Thanks!
Solid calcium bicarbonate (Ca(HCO3)2) reacts with aqueous hydrochloric acid (HCl) to form aqueous calcium chloride, liquid...
Solid calcium bicarbonate (Ca(HCO3)2) reacts with aqueous hydrochloric acid (HCl) to form aqueous calcium chloride, liquid water, and carbon dioxide gas. (a) Write the balanced molecular equation, complete ionic equation, and net ionic equation for the process. [Hint: Don’t forget the physical states of the reactants and products.] Balanced Molecular Equation: Complete Ionic Equation: Net Ionic Equation: (b) A CHEM 104 student is trying to carry out this reaction in the laboratory. What is the minimum amount of 0.2102 M...
Empirical Formula Determination 1. The following reaction is carried out to completion with excess zinc metal...
Empirical Formula Determination 1. The following reaction is carried out to completion with excess zinc metal and with a solution of iron chloride of unknown chemical composition: Fe?Cl? + Zn---->Fe + ZnCl2 Initial grams FeCl 2.071 g Grams/mole Zn=65.39 Grams/mole Fe=55.847 0.708 g of collected, dried iron metal is obtained by the end of the procedure. Using any method you choose, determine the empirical formula for iron chloride? (Atomic mass of Cl = 35.453 g/mol.) 2. Using the chemical formula...
1.      Calculate the standard free energy change at 500 K for the following reaction. Cu(s) +...
1.      Calculate the standard free energy change at 500 K for the following reaction. Cu(s) + H2O(g) à CuO(s) + H2(g) ΔH˚f (kJ/mol) S˚ (J/mol·K) Cu(s)    0    33.3    H2O(g)    -241.8    188.7    CuO(s)    -155.2    43.5    H2(g)     0    130.6 2.      When solid ammonium nitrate dissolves in water, the resulting solution becomes cold. Which is true and why? a.      ΔH˚ is positive and ΔS˚ is positive b.      ΔH˚ is positive and ΔS˚...
1. Nickel, a common metal used in a variety of alloys, is purified via the Mond...
1. Nickel, a common metal used in a variety of alloys, is purified via the Mond process to a very high (> 99.99%) purity. One of the steps in the Mond process involves the reaction of solid nickel with carbon monoxide to produce Ni(CO)4, as shown in the unbalanced equation below. Ni(s) + CO(g) → Ni(CO)4(g) How much carbon monoxide, in grams, is required to purify an impure sample containing 4.22 kg of nickel? (to the correct number of sig...
At equilibrium conditions, three gas-phase reactions carried out in a 1.5m3 batch reactor are found to...
At equilibrium conditions, three gas-phase reactions carried out in a 1.5m3 batch reactor are found to have an overall conversion of A of 80% with individual reaction selectivity’s of 60% and 40% for reactions 1 and 2, respectively. Note that selectivity has the traditional definition (amount of A reacted in reaction i/ total amount reacted) A + 2B -> C + D    (1) A + D ->B             (2) C + B -> 2E + A   (3) Assuming that only A...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT