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At 25 °C and 785 Torr, carbon dioxide has a solubility of 0.0351 M in water....

At 25 °C and 785 Torr, carbon dioxide has a solubility of 0.0351 M in water. What is its solubility at 25 °C and 1310 Torr?

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Answer #1

P = K*C
where P is partial pressure
K is henry's constant
C is solubility
P1/C1 = P2/C2
initial pressure     P1 = 785 torr
initial concentration C1 = 0.0351M
final pressure        P2 = 1310 torr
final concentration   C2 =
P1/C1 = P2/C2
C2    = P2C1/P1
       = 1310*0.0351/785
       = 0.0585 M

solubility = 0.0585M >>>>> answer

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