A patient is injected with a radiopharmaceutical labeled with technetium-99m , half-life of 6.0 h, in preparation for a gamma ray scan to evaluate kidney function. The original activity of the sample was 48 μCi. What activity is μCi remains after 18 hr? After 48 hr?
amount left,= initial amount/2n
no of half lives = total time/half life time
= 18/6 = 3 lives
amount left = 48/23 = 48/8 = 6 C >>>>>> answer
no of half lives = 48/6 = 8 lives
amount left = 48/28 = 48/256 = 0.1875 Ci >>>>>> answer
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