Question

A patient is injected with a radiopharmaceutical labeled with technetium-99m , half-life of 6.0 h, in...

A patient is injected with a radiopharmaceutical labeled with technetium-99m , half-life of 6.0 h, in preparation for a gamma ray scan to evaluate kidney function. The original activity of the sample was 48 μCi. What activity is μCi remains after 18 hr? After 48 hr?

Homework Answers

Answer #1

amount left,= initial amount/2n

no of half lives = total time/half life time

                    = 18/6 = 3 lives

amount left = 48/23 = 48/8 = 6 C >>>>>> answer

no of half lives = 48/6 = 8 lives

amount left = 48/28 = 48/256 = 0.1875 Ci >>>>>> answer

                    

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