Question

Write the complete mechanism for the formation Nylon-4,10 using sebacoyl chloride as one of the starting materials. You only have to show the formation of one amide bond.

Answer 1

Answer: According to the given question the steps of formation of  Nylon-4,10 using sebacoyl chloride is preapred same as a Nylon-6,10 ; nylon 6 10
is made from hexamethylene diamine (the diamine) and
sebacoyl chloride (the diacid chloride).

hexamethylene diamene

n H2N- CH2-CH2-CH2-CH2-CH2-CH2- NH2

+

sebacoyl chloride

n Cl O=C - CH2-CH2-CH2-CH2-CH2-CH2-CH-CH2 - C=O Cl --------------------> ---[----HN- (CH2)6 -NH - OC- (CH2)8 - CO----]---n + n HCl
nylon 6 10

The diamine and the diacid chloride bond together, end-on-end, to form
very long chains.

and for  Nylon-4,10,

H2N- CH2-CH2-CH2-CH2- NH2

+

sebacoyl chloride

n Cl O=C - CH2-CH2-CH2-CH2-CH2-CH2-CH-CH2 - C=O Cl


------>

---[----HN- (CH2)4 -NH - OC- (CH2)8 - CO----]---n + n HCl

nylon 4 10

Hence it is all about the given question . Thank you .