Question

A) what is the amount of heat lost in kj for 50 ml of water going from 70 c to 1 c

B) if all the heat from previous question went to melt 30 g of ice, what is the heat of fuion of ice in KJ/g?

C) what are you assuming the initial temperatire of ice when you did part B?

Answer 1

a. volume of water = 50 ml
density of water = 1 g/ml
mass = volume * density
     = 50*1 = 50gm
specific heat of water = 4.18 j/g-c
Q = mct
= 50*4.18*(1-70)
= -50*4.18*69
= -14421 j
= -14.421Kj
b.
ice melt at OC⁰
haet of fusion of water = 335j/g
haet of ice Q = m*heat of fusion
              = 30*335
              = 10050joules/g
              = 10.050kj/g
c. initial temperature of ice is 1C⁰