Question

Ammonia is produced using the Haber process: 3 H2 + N2 → 2 NH3 What mass of NH3 could be produced if 12.5 g H2 reacts with excess nitrogen? 4.13g, 105g, 142g, 70.4g

Answer 1

reaction take place as follow

3H₂ + N₂ 2NH₃

According to reaction 3 mole of H₂ react with 1 mole of nitrogen

molar mass of H₂ = 2.01 g/mol that mean 1 mole of H₂ = 2.01 gm then 3mole of H₂ = 6.03 gm

molar mass of NH₃ = 17.031 gm/mol that mean 1 mole of NH₃ = 17.031 gm 2mole NH₃ =34.062 gm

According to reaction 3 mole of H₂ produce 2 mole of NH₃ that mean 6.03 gm of H₂ produce 34.062 gm of NH₃ then 12.5 gm of H₂ produce 1.0534.062/6.03 = 70.4 gm

Answer is 70.4 gm