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Ammonia is produced using the Haber process: 3 H2 + N2 → 2 NH3 What mass...

Ammonia is produced using the Haber process: 3 H2 + N2 → 2 NH3 What mass of NH3 could be produced if 12.5 g H2 reacts with excess nitrogen? 4.13g, 105g, 142g, 70.4g

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Answer #1

reaction take place as follow

3H2 + N2 2NH3

According to reaction 3 mole of H2 react with 1 mole of nitrogen

molar mass of H2 = 2.01 g/mol that mean 1 mole of H2 = 2.01 gm then 3mole of H2 = 6.03 gm

molar mass of NH3 = 17.031 gm/mol that mean 1 mole of NH3 = 17.031 gm 2mole NH3 =34.062 gm

According to reaction 3 mole of H2 produce 2 mole of NH3 that mean 6.03 gm of H2 produce 34.062 gm of NH3 then 12.5 gm of H2 produce 1.0534.062/6.03 = 70.4 gm

Answer is 70.4 gm

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