Question

A stock solution of .30 M NaOH solution WILL BE DDILUTED TO THESECONCENTRATION USING THE SOLUTION OF NaCl. Show how it will prepared 10Ml of the following solution from the stuck solution provided: Solution 1: .30 M NaOH Solution 2: .24 M NaOH Solution3: .21 M NaOH Solution4: .18 M NaOH Solution5: .15 M NaOH Solution6: .05 M NaOH

Answer 1

M = 0.3 NAOH

1)

0.3, just pour 10 ml of stock solution

2)

0.24 M of NaOH

M1V1 = M2V2

V1 = M2V2/M1 = 0.24/0.3*10 = 8 ml of original solution, then add 2 ml of water

3)

0.21 M of NaOH

M1V1 = M2V2

V1 = M2V2/M1 = 0.21/0.3*10 = 7 ml of original solution, then add 3 ml of water

4)

0.18 M of NaOH

M1V1 = M2V2

V1 = M2V2/M1 = 0.18/0.3*10 = 6 ml of original solution, then add 4ml of water

5)

0.15 M of NaOH

M1V1 = M2V2

V1 = M2V2/M1 = 0.15/0.3*10 = 5 ml of original solution, then add 5 ml of water

6)

0.05 M of NaOH

M1V1 = M2V2

V1 = M2V2/M1 = 0.05/0.3*10 = 1.6 ml of original solution, then add 8.33 ml of water