Question

1) Tungsten (W) reacts with Cl2 to form WCl6. What mass of WCl6 is formed from...

1) Tungsten (W) reacts with Cl2 to form WCl6. What mass of WCl6 is formed from the reaction of 12.6 g W with 13.6 g Cl2?

2) NH3 reacts with O2 to produce NO and H2O. How many moles of O2 are needed to react with exactly 10.0 moles of NH3?

Homework Answers

Answer #1

W + 3Cl2 ----> WCl6

this is the balanced reaction

one mole of W required 3 mole of Cl2

no of moles of W = weight of W / molar mass of W

= 12.6 / 183.84

= 0.0685 mol

n of mole of Cl2 = 13.6 / 70.9

= 0.2 moles

now 0.0685 moles required 3 x 0.0685 moles of Cl2 = 0.2 moles

0.0685 moles W will give 0.0685 moles WCl6

weight of WCl6 = no of moles of WCl6 x molar mass of WCl6

= 0.0685 x 396.6

= 27.17 grams will produce

2)

first write the balanced equation

4 NH3 + 5 O2 -----> 4 NO + 6 H2O

from the equation it is clear that

4 mole of NH3 required 5 moles of O2

or

1 mole of NH3 required 5/4 moles of O2

similarly

10 mol of NH3 required 10 x 5/4 moles of O2

12.5 moles of O2 required

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