Question

A chemist adds 300.0mL of a 0.166/molL aluminum sulfate Al2SO43 solution to a reaction flask. Calculate the millimoles of aluminum sulfate the chemist has added to the flask. Round your answer to 3 significant digits.

Answer 1

concentration, C = 0.166 mol/L
Volume = 300 mL = 0.3 L

number of moles = concentration * volume
                                     = 0.166 mol/L * 0.3 L
                                     =0.0498 mol
                                     = 49.8 millimoles

Answer: 49.8 millimoles