Question

what is the molarity of a 300 ml solution containing 5.5g NaCl?

Answer 1

Given:

Volume of solution = 300 mL

Mass of NaCl = 5.5 g

Solution:

Molarity is the concentration term and can be mathematically expressed as follow.

Molarity = number of moles of solute / volume of solution in L

To get molarity of above solution we should know the moles of sodium chloride.

Now we need to use mol formula.

Number of moles = Mass in g / molar mass

Molar mass of sodium chloride = 58.443 g /mol

Number of moles of NaCl = 5.5 g / 58.443 g per mol = 0.09411 mol

Molarity of sodium chloride solution = 0.09411 mol / (300 x 10^-3 L )

= 0.314 M

[NaCl]= 0.314 M