Question

How can I prepare 2M sucrose (342.5965g/ mol) in methanol? Please provide me with the procedure. Thanks.

Answer 1

Let the volume of the soltion be 1L

We know that Molarity , M = number of moles / volme of the solution in L

2 M = number of moles / 1 L

So number of moles of sucrose , n = 2 x 1 = 2 mol

Also number of moles , n = mass/molar mass

Mass , m = number of moles x molar mass

= 2 mol x 342.5965 g/mol

= 685.193 g

So exactly weigh and transfer 685.193 g of sucrose in a 2L volumetric flask and add littile amount of methanol to the flask , dissolve all the sucrose in it and finally made upto the mark of the vessel with methanol we get 2M sucrose solution in methanol.