Consider the following reaction: 3Cu(NO3)2 (aq) + 2CrCI3 (aq) ---> 3CuCI2 (s) + 2Cr(NO3)3 (aq)
-In the lab you mixed 36 grams of copper (II) nitrate with an excess amount of chromium(III) chloride. How many moles of chromium(III) nitrate would you produce.
-What is the percent yield if you actually produced 15.5 g of chromium(III) nitrate?
Get Answers For Free
Most questions answered within 1 hours.