which of the following orbital designation is (are) not possible?
2f
4s
1d
5p
The question is based on quantum numbers. We have to remember the rules for permissible quanum numbers of an orbital.
For principal Quantum No. 'n' the Azimuthal quantum 'l' No. can have any values from 0 to n-1.
Similarly for quantum No. 'l' magnetic quantum number can have any value from -l to +l
(A) 2f
n = 2, l = 3. Hence this Orbital is NOT POSSIBLE because l is greater than n.
(B) 4s
n = 4; l =0. This orbital is POSSIBLE
(C) 1d
n = 1; l =2. Hence this Orbital is NOT POSSIBLE because l is greater than n.
(D) 5p
n = 5; l = 1 . This orbital is POSSIBLE
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