Question

C3H8 (l) + 5O2 (g) → 3CO2 (g) + 4H2O (l) A)How much work is done...

C3H8 (l) + 5O2 (g) → 3CO2 (g) + 4H2O (l)

A)How much work is done at 1.2 atm and 334 K when 1 mole of propane undergoes combustion?

B)How much work is done at 1.2 atm and 310 K when 102 grams of oxygen reacts with excess propane in this combustion reaction.?

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Homework Answers

Answer #1

IF:

C3H8(l) + 5O2(g) → 3CO2(g) + 4H2O (l)

THEN:

A)How much work is done at 1.2 atm and 334 K when 1 mole of propane undergoes combustion?

B)How much work is done at 1.2 atm and 310 K when 102 grams of oxygen reacts with excess propane in this combustion reaction.?

1C3H8(l) + 5O2(g) → 3CO2(g) + 4H2O (l)

1molC3H8(l) x 44g/mol + 5molO2(g) x 32g/mol → 3molCO2(g) x 44g/mol+ 4molH2O (l) x 18g/mol

44g C3H8(l) + 160g O2(g) → 132g CO2(g) + 72g H2O

when 102 grams of oxygen reacts with excess propane in this combustion reaction how many moles of each specie form or reac?

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