Question

Write the balanced molecular, ionic, and net-ionic form of each equation.

1) rubidium hydroxide + nitric acid --> ?

2) hydrochloric acid + sodium oxalate--> ?

3) iron(II) sulfate + sodium phosphate--> ?

4) iron (III) perchlorate + aqueous ammonia--> ?

Answer 1

RbOH (aq) + HNO3(aq) -----> RbNO3(aq) + H2O(l)

ionic equation

Rb⁺(aq) +OH^- (aq) + H⁺(aq)+NO3^-(aq) -----> Rb⁺(aq)+NO3^-(aq) + H2O(l)

removal of spectetor ions

net ionic equation

H⁺(aq) + OH^-(aq) -----> H2O(l)

2. 2HCl(aq) + Na2C2O4(aq) -----> H2C2O4(aq) + 2NaCl(aq)

ionic equation

2H⁺(aq)+Cl^-(aq) + 2Na⁺(aq)+C2O4^2-(aq) -----> 2H⁺(aq)+C2O4^2-(aq) + 2Na⁺(aq)+2Cl^-(aq)

3. 3FeSO4(aq) + 2Na3PO4(aq)-----> Fe3(PO4)2(s) +3 Na2SO4(aq)

ionic equation

3Fe⁺²(aq) +3 SO4^2-(aq) + 6Na⁺(aq)+2PO4^3-(aq)-----> Fe3(PO4)2(s) + 6Na⁺+3SO4^2-(aq)

removal of spectetor ions

3Fe²⁺(aq) +2 PO4^3-(aq) -----> Fe3(PO4)2(s)

4. Fe(ClO4)3(aq) + 3NH3(aq) +3 H20(l) ----> Fe(OH)3(s) + 3NH4ClO4(aq)

ionic equation

Fe⁺³(aq) + 3(ClO4)^-(aq) + 3NH3(aq) +3H⁺(aq)+ 3OH^-(aq)----> Fe(OH)3(s) + 3NH4⁺(aq)+3ClO4^-(aq)

removal of spectetor ions

Fe⁺³ (aq) + 3OH^-(aq) -----> Fe(OH)3(s) NET IONIC EQUATION