Question

11. The reaction NO(g) + ½ Cl2(g) –––> NOCl(g) has ΔH = –44 kJ. The activation energy for this reaction is 59 kJ/mol. What is the activation energy for the reverse reaction? A) 59 kJ/mol B) 15 kJ/mol C) 103 kJ/mol D) –44 kJ/mol E) –103 kJ/mol

Answer 1

Solution :-

for the forward reaction delta H = -44 kJ means it loses this amount of heat

And the activation energy is 59 kJ/mol

therefore activation energy for the reverse reaction is acalculated as

Ea reverse = Ea forward - DeltaHforward

                = 59 kJ/mol - ( -44 kJ/mol )

               = 103 kJ/mol

So the correct answer is option C