Question

Copper carbonate hydrate produces 1 mole of water (MM = 18.015 g/mol) for every mole of solid product (MM = 79.545 g/mol) produced. Given that 3.327 g of solid product were produced during the reaction, how many grams of water were released as water vapor? (number of moles = mass (g)/ molar mass (g/mol)).

Answer 1

Given that;

Copper carbonate hydrate produces 1 mole of water for every mole of solid product produced.

1 mole of water ;MM = 18.015 g/mol

Copper carbonate hydrate; MM = 79.545 g/mol

Copper carbonate hydrate = 3.327g

First calcualte the number of moles Copper carbonate hydrate in 3.327 g as follows:

3.327 g Copper carbonate hydrate/79.545 g/mol

= 0.042 mol Copper carbonate hydrate

Now 0.042 mol Copper carbonate hydrate will produce mole of water =

0.042 mol Copper carbonate hydrate * 1 mol of water /1.0 mol Copper carbonate hydrate

= 0.042 mol of water

Now convert it into mass as follows:

0.042 mol of water * 18.015 g/mol

= 0.75 g water