Use the ΔHrxn values of the following reactions:
2 SO2 (g) + O2 (g) → 2 SO3 (g) ΔHrxn = -196 kJ
1/4 S8 (s) + 3 O2 (g) → 2 SO3 (g) ΔHrxn = -790 kJ
to calculate the ΔHrxn value of this reaction:
1/8 S8 (s) + O2 (g) → SO2 (g)
given reactions are
2 SO2 (g) + O2 (g) → 2 SO3 (g) ΔHrxn = -196 kJ (1)
1/4 S8 (s) + 3 O2 (g) → 2 SO3 (g) ΔHrxn = -790 kJ (2)
to calculate the ΔHrxn value of this reaction: 1/8 S8 (s) + O2 (g) → SO2 (g) (3)
Eq.2- Eq.1 gives
1/4S8+3O2-2SO2-O2--à0 ΔHrxn=-790+196=-594 Kj (4)
1/4S8+ 2O2--à 2SO3 ΔHrxn=-594 Kj (5)
Dividing Eq.5 by 2 gives 1/8S8+ O2--à SO3 ΔHrxn=-594/2=-297 Kj
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