Question

The ionization energy for a hydrogen atom in its ground state is 13.6 eV. Hence the ionization energy for a ground-state He+ ion is?

Please explain!

Answer 1

IE    = 13.6 Z^2/n^2 ev

Z = atomic number

n = shell number

for hydrogen    Z = 1

for ground state n = 1

IE   = 13.6*(1)^2/(1)^2   = 13.6 ev for hydrogen

For He^+    Z = 2

                n = 1 for ground state

IE    = 13.6*(2)^2/(1)^2 ev

       = 13.6*4 ev

        = 54.4ev >>>>answer