Question

What mass of ethylene glycol (C2H6O2) is required to lower the freezing point of 50.0 g of water by 10.0oC?

Answer 1

Freezing point depression constant for water = 1.86°/mol
Your depression was 10°C.
                                               62.04 x 10 /1.86 = 333.54
Quantity of solute to be dissolved = 333.54 x 50 /1000 = 16.67 gm of ethylene glycol (C2H6O2)

ethylene glycol Molar mass: 62.07 g/mol