Question

52.0 mL of a 1.70 M solution is diluted to a total volume of 258 mL. A 129-mL portion of that solution is diluted by adding 109 mL of water. What is the final concentration? Assume the volumes are additive.

Answer #1

volume of solution = 52 mL

concentration = 1.70 M

diluted to total volume of = 258 mL

the dilution formula is :

M1 V1 = M2 V2

1.70 x 52 = M2 x 258

M2 = 0.343 M

millimoles of diluted portion = 129 x 0.343 = 44.25

total volume = 129 + 109 = 238 mL

the final concentration = 44.25 / 238

= 0.186 M

**the final concentration = 0.186 M**

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