52.0 mL of a 1.70 M solution is diluted to a total volume of 258 mL. A 129-mL portion of that solution is diluted by adding 109 mL of water. What is the final concentration? Assume the volumes are additive.
volume of solution = 52 mL
concentration = 1.70 M
diluted to total volume of = 258 mL
the dilution formula is :
M1 V1 = M2 V2
1.70 x 52 = M2 x 258
M2 = 0.343 M
millimoles of diluted portion = 129 x 0.343 = 44.25
total volume = 129 + 109 = 238 mL
the final concentration = 44.25 / 238
= 0.186 M
the final concentration = 0.186 M
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