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The vapor pressure of liquid methanol, CH3OH, is 100. mm Hg at 294 K. A 4.26×10-2...

The vapor pressure of liquid methanol, CH3OH, is 100. mm Hg at 294 K. A 4.26×10-2 g sample of liquid CH3OH is placed in a closed, evacuated 310. mL container at a temperature of 294 K.

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Answer #1

Solution.

Let's assume that the amount of methanol placed into the container is not enough to sustain the pressure of saturated vapor - 100 mmHg. If this assumption is wrong, the pressure at equilibrium is exactly 100 mmHg.

Checking the initial assumption.

Converting the values given to SI units:

V = 0.00031 m3
T = 294 K;
m = 4.26*10-5 kg
M = 0.03204 kg/mol
R = 8.314 J/(mol*K)
Calculated pressure is P = 10484 Pa;
Converting pressure to millimetre of mercury: P = 78.6 mmHg < 100 mmHg => the initial assumption is correct.

Answer: 10484 Pa.

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