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1. A 0.0352 g sample of pure calcium carbonate (100.09 g/mol) was dissolved in acid and...

1. A 0.0352 g sample of pure calcium carbonate (100.09 g/mol) was dissolved in acid and titrated to its endpoint with newly made EDTA titrant (~0.010 M) according to the procedure given below. The starting burette volume was 0.10 mL. The ending burette volume was 35.52 mL. Calculate the exact concentration of the EDTA titrant. Show all work.

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Answer #1

The mass of calcium carbonate is 0.0352 g. The formula mass of calcium carbonate is 100.09 g/mol.The number of moles of calcium carbonate are moles.

0.0003517 moles of calcium carbonate will react with 0.0003517 moles of EDTA.

The inital burette volume is 0.10 mL. The final burette volume is 35.52 mL. The volume of EDTA used for the titration is 35.52 - 0.10 = 35.42 mL. Let C mol/L be the molar concentration of EDTA.

Hence, the exact concentration of the EDTA titrant is 0.009929 M

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