calculate the theoretical yield and the number of grams of hydrobenzoin that would form if every mole of the limiting reagent were converted 100% to product. Show all working and state the limiting reagent.
Here we know from each limiting reactant we get only one moles of hydrbenzoin. Mole ration between limiting reactant and the product so we get one mole of hydrobenzoin from one mole of reactant.
Now we use following molar mass of hydrobenzoin.
Molar mass of hydrobenzoin = 214.26 g /mol
Mass in g = Moles x molar mass
Mass in g = 1mol x 214.26 g = 214.26 g
Since we know when moles of limiting reactant used to find mole so product and further mass, we call mass is a theoretical mass.
So the theoretical mass or yield = 214.26 g
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