Question

You have 5 mL of 0.01M acetic acid and 3 mL of 0.02 M sodium acetate in a 50 mL buffer solution. What is the total buffer concentration measured as total [OAc-]?

Answer 1

Answer – We are given, 5 mL of 0.01M acetic acid and 3 mL of 0.02 M sodium acetate in a 50 mL buffer solution

First we need to calculate the moles of acetate

Moles of acetate = 0.02 M *0.003 L

                           = 6.0*10^-5 moles

Total volume = 50 mL

So, total concentration of [OAc^-] = 6.0*10^-5 moles /0.050 L

                                                       = 0.0012 M