Question

Consider the fructose-1,6-bisphosphatase reaction. Calculate the free energy change if the ratio of the concentrations of the products to the concentrations of the reactants is 21.3, and the temperature is 37.0 °C? ΔG°\' for the reaction is –16.7 kJ/mol. The constant R = 8.3145 J/(mol·K)

Answer 1

For any reaction,

Q=ratio of concentration of product to reactants=[products]/[reactants]

G=Go+ RT ln Q

T=37C=273+37=310K

Also, Go=-16.7 kj/mol

G=Go+ RT ln Q=-16.7kj/mol+RTlnQ=-16.7 kj/mol+ (8.3145 J/K mol)(310K) ln (21.3)=-16.7kj/mol+7883.80J/mol=-16.7kj/mol+7.883kj/mol=-8.817 kj/mol(answer)