Question

If there are 4.60 mol of O, how many of each of the following compounds are...

If there are 4.60 mol of O, how many of each of the following compounds are present?

H2SO4

C2H4O2

NaOH

Homework Answers

Answer #1

Given that moles of O = 4.6 mol

1) H2SO4

1 mol of H2SO4 = 2 mol of H + 1 mol of S + 4 mol of O

Hence,

1 mol of H2SO4 = 4 mol of O

So, ? mol of H2SO4 = 4.6 mol of O

? = 1 mol of H2SO4 x (4.6 mol of O / 4 mol of O)

= 1.15 mol of H2SO4

Therefore, 1.15 mol of H2SO4 is present.

2) C2H4O2

1 mol of C2H4O2 = 2 mol of C + 4 mol of H + 2 mol of O

Hence,

1 mol of C2H4O2 = 2 mol of O

So, ? mol of C2H4O2 = 4.6 mol of O

? = 1 mol of C2H4O2 x (4.6 mol of O / 2 mol of O)

= 2.3 mol of C2H4O2

Therefore, 2.3 mol of C2H4O2 is present.

3)  NaOH

1 mol of NaOH = 1 mol of Na + 1 mol of O + 1 mol of H

Hence,

1 mol of NaOH = 1 mol of O

So, ? mol of  NaOH  = 4.6 mol of O

? = 1 mol of  NaOH  x (4.6 mol of O / 1 mol of O)

= 4.6 mol of NaOH

Therefore, 4.6 mol of  NaOH  is present.

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