Question

If there are 4.60 mol of O, how many of each of the following compounds are present?

H2SO4

C2H4O2

NaOH

Answer 1

Given that moles of O = 4.6 mol

1) H2SO4

1 mol of H2SO4 = 2 mol of H + 1 mol of S + 4 mol of O

Hence,

1 mol of H2SO4 = 4 mol of O

So, ? mol of H2SO4 = 4.6 mol of O

? = 1 mol of H2SO4 x (4.6 mol of O / 4 mol of O)

= 1.15 mol of H2SO4

Therefore, 1.15 mol of H2SO4 is present.

2) C2H4O2

1 mol of C2H4O2 = 2 mol of C + 4 mol of H + 2 mol of O

Hence,

1 mol of C2H4O2 = 2 mol of O

So, ? mol of C2H4O2 = 4.6 mol of O

? = 1 mol of C2H4O2 x (4.6 mol of O / 2 mol of O)

= 2.3 mol of C2H4O2

Therefore, 2.3 mol of C2H4O2 is present.

3)  NaOH

1 mol of NaOH = 1 mol of Na + 1 mol of O + 1 mol of H

Hence,

1 mol of NaOH = 1 mol of O

So, ? mol of  NaOH  = 4.6 mol of O

? = 1 mol of  NaOH  x (4.6 mol of O / 1 mol of O)

= 4.6 mol of NaOH

Therefore, 4.6 mol of  NaOH  is present.