Question

How do I solve?

"To treat a brain on your hand, you decide to place an ice cube on the burned skin. The mass of the ice cube is 19.8 g, and its initial temperature is -13.2 degrees C. The water resulting from the melted ice reaches the temperature of your skin, 29.2 degrees C. How much heat is absorbed by the ice cube and resulting water? Assume that all the water remains in your hand."

Answer 1

Solution :-

First ice will change from -13.2 C to 0 C

Then ice melt at 0 C

Then liquid water will change from 0 to 29.2 c

Qtotal = q ice + delta H fus + q water

            = (m* c ice *delta T)+ (m*delta H fusion )+(m*c water * delta T)

            = (19.8 g * 2.03 J per g C * 13.2 C)+(19.8 g * 334 J /g)+(19.8 g * 4.184 J per g C * 29.2 )

           = 9563 J

So the heat absorbed by ice is 9563 J or we can write it as 9.563 kJ