Question

K c is 1.29 × 102 for this reaction: H2(g) + I2(g) ↔ 2HI(g). If 0.18...

K c is 1.29 × 102 for this reaction:

H2(g) + I2(g) ↔ 2HI(g).

If 0.18 M H2 is initially mixed with 1.20 M I2, what is the concentration of H2 at equilibrium?

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Answer #1

Kc = 1.29 * 10^(2)

                        

Initial                0.18           1.20              0

Final               (0.18-x)       (1.20-x)       2x

solving the quadratic equation we get

x = 0.179027 and x = 1.24513

x = 1.24513 is not possible otherwise concentration of H will become negative

[HI] = 2 * x = 2 * 0.179027 = 0.358054M

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