If the equilibrium constant for a reaction at 25 C is 200, what is the standard free energy change for the process?
K = 200
T = 25+273 = 298K
G0 = -RTlnK
= -8.314*298ln200
= -8.314*298*5.2983
= -13127J/mole
= -13.127KJ/mole >>>>>answer
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