Sodium carbonate can be made by heating sodium
bicarbonate:
2NaHCO3(s)-->
Na2CO3(s) + CO2(g) +
H2O(g)
Given that ΔH° = 128.9 kJ/mol and ΔG° = 33.1 kJ/mol at 25°C, What
is the value of ΔS°
Answer in J/mol K to 3 sig figs.
The standard Gibbs free energy ΔG° is related to standard enthalpy change ΔH° and standard entropy change ΔS° as
ΔG° = ΔH°-TΔS°
Where T is the temperature in K
Given that ΔH° = 128.9 kJ/mol
ΔG° = 33.1 kJ/mol
T = 25 C = 273+25 K = 298 K
33.1 kJ/mol = 128.9 kJ/mol - 298K*ΔS°
33.1 kJ/mol -128.9 kJ/mol = - 298K*ΔS°
-95.8 kJ/mol = - 298K*ΔS°
ΔS° = -95.8 kJ/mol/- 298K
= -95.8*1000 J/mol/- 298K
= 321.476 J/mol-K
Rounding off to 3 significant figures we have ΔS° = 321 J/mole-K
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