For the reaction
N2(g)+3H2(g)⇌2NH3(g)
Kp = 3.80×10−3 at 253 ∘C . What is K for the reaction at this temperature?
Enter your answer numerically.
Solution :-
formula to calculate the Kp form the K is
Kp = K* (RT)^delta n
delta n= sum of coefficient of product - sum of coefficient of reactant
= 2 - (3+1)
= -2
now lets calculate the K
Kp = K* (RT)^delta n
253 C + 273 = 526 K
3.80*10^-3 = K * (0.08206 L atm per mol K * 526 K)^-2
3.80*10^-3/ (0.08206 L atm per mol K * 526 K)^-2 = K
7.08 = K
So the K value is 7.08 at the given temperature.
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