if the slope of the calibration curve of absorbance vs concentration is 0.0681x+0 (mg/mL) how would I determine the concentration of a diluted solution (1/8 diluted with 0.424 absorbance)
From the slope
slope of calibration curve = molar absorptivity
= 0.0681 M-1.cm-1
with an absorbance of 0.424
concentration = absorbance/molar absorptivity
= 0.424/0.0681
= 6.23 M
This is for diluted solution
So concentration of original solution = 6.23 x 8
= 49.84 M
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