Question

Create 100 mL buffer containing ethanoic acid (0,100 M) and ethanoate (0,100 M)

Answer 1

Solution :-

volume = 100 ml = 0.100 L

molarity ethanoic acid = 0.100 M , acetate = 0.100 M

lets calculate the moles of the ethanoic acid and acetate needed

moles = molarity * volume in liter

moles of ethanoic acid = 0.100 mol per L * 0.100 L = 0.01 mol

moles of acetate = 0.100 ,mol per L * 0.100 L = 0.01 mol

now lets calculate the mass of the ethanoic acid and acetate needed to make the solution

mass = moles * molar mass

mass of ethanoic acid = 0.01 mol * 60.05 g per mol = 0.6 g ethanoic acid

mass of sodium acetate = 0.01 mol * 82.0343 g per mol = 0.82 g sodium acetate.

so we need to use 0.6 g ethanoic acid and 0.82 g sodium acetate and dissolve them to make the solution of 100 ml of final volume.