Question

Over the years, the thermite reaction has been used for welding railroad rails, in incendiary bombs,...

Over the years, the thermite reaction has been used for welding railroad rails, in incendiary bombs, and to ignite solid-fuel rocket motors. The reaction is the following. MoO3(s) + 2 Al(s) → Mo(l) + Al2O3(s) What masses of molybdenum(VI) oxide and aluminum must be used to produce 14.3 g of molybdenum? What is the maximum mass of aluminum oxide that could be produced?

Atomic weight of MO= 96, Molecular weight of Oxygen =16, Atomic weight of aluminium =27

Molecular weight of MOO3= 96+3*16= 144 and that of Al2O3= 27*2+48= 102

Moles of molybdenum = 14.3/ 96= 0.149 moles

From the reaction MOO3+ 2Al---->MO(l) +Al2O3(s)

1 mol of Mo requires 1moe of MOO3 and 2moles of Aluminium

Since Moles= mass/ molecular weight and mass =Molecular weight* moles

0.1489 moles of Mo requires 0.149 moles of MOO3=(0.149* 144gms =21.456 gms) and 2*0.149 moles of Al = (0.298*27gms= 8.05 gms of Al)

Maximum Amount of Al2O3 that can be formed= 0.149 moles* molecular weight of Al2O3= 0.149*102=15.2 gms

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