Question

How much heat energy does 50.0 grams of water absorb if its temperature goes from 22.0 °C to

25.3°C? can you please explain with dymentional analysis?

Answer #1

**Solution :-**

The mass of water m = 50.0 g

initial temperature of water = 22.0 C

final temperature of water T2 = 25.3 C

heat absorbed = ?

using the formula q = m*c*delta T we can calculate the amount of heat absorbed

q= heat , m = mass of water , c= specific heat of water (4.184 J per g C)

delta T= change in temperature

lets put the values in the formula

q= 50.0 g * 4.184 J per g C * (25.3 C - 22.0 C)

q= 690.36 J

**So the amount of heat absorbed by water = 690.36
J**

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