Question

How much heat energy does 50.0 grams of water absorb if its temperature goes from 22.0...

How much heat energy does 50.0 grams of water absorb if its temperature goes from 22.0 °C to

25.3°C? can you please explain with dymentional analysis?

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Answer #1

Solution :-

The mass of water m = 50.0 g

initial temperature of water = 22.0 C

final temperature of water T2 = 25.3 C

heat absorbed = ?

using the formula q = m*c*delta T we can calculate the amount of heat absorbed

q= heat , m = mass of water , c= specific heat of water (4.184 J per g C)

delta T= change in temperature

lets put the values in the formula

q= 50.0 g * 4.184 J per g C * (25.3 C - 22.0 C)

q= 690.36 J

So the amount of heat absorbed by water = 690.36 J

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