Question

Complete the following metric equalities (show your work):

28 ml = ____________________________ kL

0.35 gallon= ________________________ mL

B. A metal bar of 2.15g/ml density has volume of 24 ml. Calculate mass of metal bar:    _______________________

C. Boiling water is at 100 degree celcius. Convert it in Farenheit scale: ________________________________

Answer 1

Answer – A) We are given, units and we need to convert the given unit to respective another units

1)28 ml = ? kL

We know

1 mL = 0.001 L

1 L = 0.001 kL

So, = 28 mL * 0.001 L / 1 mL * 0.001 kL / 1 L

       = 2.8*10^-5 kL

2) 0.35 gallon = ? mL

We know

1 gal = 3785.4 mL

So, 0.35 gal = ?

= 1325 mL

B) Given, mass = ? , density of metal bar = 2.158 g/mL , volume = 24 mL

We know

Density = mass / volume

So,

Mass = density * volume

         = 2.15 g/mL * 24 mL

         = 51.6 g

mass of metal bar is 51.6 g

C) Given, boiling point = 100^oC and we need to converted to ^oF

We know

T(^oF) = T(^oC)*9/5 + 32

          = 100^oC * 9/5 + 32

          = 212.0 ^oF