Question

The data below show the concentration of N2O5 versus time for the following reaction: N2O5(g)→NO3(g)+NO2(g) Time...

The data below show the concentration of N2O5 versus time for the following reaction:

N2O5(g)→NO3(g)+NO2(g)
Time (s) [N2O5] (mol L−1)
0 1.000
25 0.822
50 0.677
75 0.557
100 0.458
125 0.377
150 0.310
175 0.255
200 0.210

Determine the order of the reaction.

Homework Answers

Answer #1

Answer: Rate=K[N2O5] and it's a first order reaction

The best way to find the rate constant for a first order reaction is to graph the natural log of the concentration vs time. The slope is the negative of the rate constant.

Instead, I used the formula

ln (A/Ao) = -kt

and solved for k using 1.000 as Ao and the concentrations you give as A and the times as t.


At 25 sec, I got 7.84 x 10^-3, at 50 sec I got 7.80 x10^-3, then 7.80, then 7.81, then 7.81, then 7.80 (always x 10^3). So, I'd be willing to call the rate constant 7.81 x 10^-3 though you might argue for simply 7.8 x 10^-3 and it's important to know how exactly the time was measured.

The units are sec ^-1

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Determine the order of reaction 2 N2O5 --> (g)4 NO2 (g) + O2 (g) using the...
Determine the order of reaction 2 N2O5 --> (g)4 NO2 (g) + O2 (g) using the following information: t (min) 0 1 2 3... infinity [O2] (mol/L) 0 0.148 0.252 0.326... 0.500
The data below show the concentration of ABversus time for the following reaction: AB(g)→A(g)+B(g) Time (s)...
The data below show the concentration of ABversus time for the following reaction: AB(g)→A(g)+B(g) Time (s) [AB] (M) 0 0.950 50 0.459 100 0.302 150 0.225 200 0.180 250 0.149 300 0.128 350 0.112 400 0.0994 450 0.0894 500 0.0812 Determine the order of the reaction.
1. Dinitrogen pentoxide (N2O5) decomposes to NO2 and O2 at relatively low temperatures in the reaction...
1. Dinitrogen pentoxide (N2O5) decomposes to NO2 and O2 at relatively low temperatures in the reaction 2N2O5(soln) → 4NO2(soln) + O2(g) This reaction is carried out in a CCl4 solution at 45° C. The concentrations of N2O5 as a function of time are listed in the table. Plot a graph of the concentration versus t, ln (natural log) concentration versus t, and 1/concentration versus t. Graphically, determine the order of the reaction, write the rate law and calculate the value...
Consider the reaction: NO2(g) ® NO(g) + ½ O2(g). The data below were collected for the...
Consider the reaction: NO2(g) ® NO(g) + ½ O2(g). The data below were collected for the concentration of NO2 as a function of time. a)Determined the average rate of the reaction between 10 and 20 s. b)Determine the rate of appearance of O2(g) between 10.0 and 20.0 sec Time (s) 0.0 10.0 20.0 30.0 40.0 50.0 [NO2] (M) 1.000 0.951 0.904 0.860 0.818 0.778
Time(s) Concentration (M) N2O5 NO2 O2 0 0.0200 0 0 100 0.0169 0.0063 0.0016 200 0.0142...
Time(s) Concentration (M) N2O5 NO2 O2 0 0.0200 0 0 100 0.0169 0.0063 0.0016 200 0.0142 0.0115 0.0029 300 0.0120 0.0160 0.0040 400 0.0101 0.0197 0.0049 500 0.0086 0.0229 0.0057 600 0.0072 0.0256 0.0064 700 0.0061 0.0278 0.0070 Concentrations as a Function of Time at 55 ∘ for the Reaction 2N2O5(g)⟶4NO2(g)+O2(g) A) Use the data in the table to calculate the average rate of decomposition of N2O5 during the time interval 100-200 s B) Use the data in the table...
The reaction A → C was performed and the concentration vs. time data below collected. time,...
The reaction A → C was performed and the concentration vs. time data below collected. time, s 0 1 2 3 4 5 6 7 8 [A], mol/L 0.7905 0.5041 0.3214 0.2049 0.1307 0.08332 0.05313 0.03388 0.02160 Complete the rate law for the reaction by filling in the values for the rate constant and reaction order. Rate = k[A]x rate constant (without units) = reaction order =
TWO MOLECULES OF BUTADINEC4H6 CAN JOIN TO FORM C8H12. C4H6----1/2C8H12 THE FOLLOWING CONCENTRATION VERSUS TIME DATA...
TWO MOLECULES OF BUTADINEC4H6 CAN JOIN TO FORM C8H12. C4H6----1/2C8H12 THE FOLLOWING CONCENTRATION VERSUS TIME DATA WERE COLLECTED AT 500DEGREE C TIME(SEC) [C4H6](mol/Lu*100 TIME(SEC) [C4H6]mol/L*100) 0 ? 195 1.62 41.40 .84 604 1.47 4655 .80 1246 1.29 6210 .68 2180 1.10 8135 .57 A.DETERMINE GRAPHICALY THE ORDER OF REACTION WITH RESPECT TO C4H6,AND WRITE THE RATE LAW. B. WHAT IS THE RATE CONSTANT THE REACTION AS DETERMINED FROM THE GRAPH. C.WHAT IS THE INITIAL CONCENTRATION OF C4H6 (AT SEC) D.WHAT...