Question

1.First you need to find the number of valance electrons in Ch3Cl. The number of valance electrons in an atom of an element is equal to the last digit in the group number of that element in the periodic table.

C is in group____ H is in group ____ Cl is in group _____

In CH3Cl there is a total of ____ valence electrons.

2. the model consists of balls and sticks. What kind of ball should you select for the c atom? ______ the H atom? ____ the Cl atom? ____ The electrons in the molecule are paired, and each stick represents an electron pair. How many sticks do you need? ______

3. Assemble a skeleton structure for the molecule, connecting the ball with sticks into one unit. Use the rule that C atoms form four bonds, whereas Cl atoms usually do not. Draw a sketch of the skeleton below:

4. How many sticks did you need to make the skeleton structure? _____ How many sticks are left over? ____ If your model is to obey the octet rule each ball must have hour sticks in it (except for hydrogen atom balls, which need only one). (Each atom in an octet rule species is surrounded by four pairs of electrons.) How many holes remain to be filled? ____ Fill them with remaining sticks, which represent nonbonding electron pairs. Draw the complete Lewis structure for CH3Cl using lines for bonds and pairs of dots for nonbonding electrons.

5. describe the geometry of the model, which is that of CH3Cl ____ Is the CH3Cl molecule polar? ___ why?

would you expect CH3Cl to have any isomeric forms? ____ Explain your reasoning.

6. Would CH3Cl have any resonance structures? ______ If so, draw them below.

Answer 1

The number of valance electrons in an atom of an element is equal to the last digit in the group number of that element in the periodic table.

In this line, we can write

Carbon is in group 14 and hence carbon contains 4 valence electron

Hydrogen is in group 1 and hence hydrogen contains 1 valence electron

Chlorine is in group 17 and henc it contains 7 valence electrons

The above findings are validated by the electronic configuration of these elements presented below.

so total valence electron in CH₃Cl

= 4 (for carbon) + (1 x 3) (for 3 hydrogen) + 7 (for chlorine) = 4 + (3x1) + 7 = 14 electrons